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Geometry4.23 The Area of a Sector - I

 Example: The radius of a circle is 28 cm. An arc AB subtends an angle of 105° at the center O. Find the area of the sector OAB. Solution: Given that, r = 28 cm, and x° = Ð AOB = 105 ° The area of the sector OAB = (x / 360) * p * r2 = (105/360) * 22/7 * 28 * 28 = (7 * 22 * 14) / 3 = 2156/3 = 718 2/3 sq cm. Directions: Read the above example carefully and answer the following questions. Also make 10 different examples of your own.

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Geometry4.23 The Area of a Sector - I

 Q 1: The radius of a circle is 8.4 cm. An arc AB subtends an angle of 135 ° at the center O. Find the area of the sector OAB.83.00 sq cm86.36 sq cm83.16 sq cm84.69 sq cm Q 2: An arc AB subtends an angle of 60 °at the center O of a circle. Find the radius of the circle if the area of the sector OAB is given by 147.84 sq cm.14.6 cm12.2 cm16.8 cm15.2 cm Q 3: The radius of a circle is 21 cm. An arc AB subtends an angle of at the center O. Find the angle if the area of the sector OAB is given by 288.75 sq cm.90°75°65°68° Q 4: The radius of a circle is 14 cm. An arc AB subtends an angle of 72 ° at the center O. Find the area of the sector OAB.123.2 sq cm135.5 sq cm136.8 sq cm12.36 sq cm Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!

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