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Date:___________________

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Geometry
4.23 The Area of a Sector - I

Example:
The radius of a circle is 28 cm. An arc AB subtends an angle of 105 at the center O. Find the area of the sector OAB.

Solution:
Given that,
r = 28 cm, and x = AOB = 105
The area of the sector OAB = (x / 360) * p * r2
= (105/360) * 22/7 * 28 * 28
= (7 * 22 * 14) / 3
= 2156/3
= 718 2/3 sq cm.


Directions: Read the above example carefully and answer the following questions. Also make 10 different examples of your own.

Name: ___________________

Date:___________________

Geometry
4.23 The Area of a Sector - I

Q 1: The radius of a circle is 8.4 cm. An arc AB subtends an angle of 135 at the center O. Find the area of the sector OAB.
83.00 sq cm
86.36 sq cm
83.16 sq cm
84.69 sq cm

Q 2: An arc AB subtends an angle of 240 at the center O of a circle. Find the radius of the circle if the area of the sector OAB is given by 102.67 sq cm.
8 cm
7 cm
9 cm
6 cm

Q 3: The radius of a circle is 28 cm. An arc AB subtends an angle at the center O. Find the angle if the area of the sector OAB is given by 985.6 sq cm.
140
122
132
144

Q 4: The radius of a circle is 14 cm. An arc AB subtends an angle of 72 at the center O. Find the area of the sector OAB.
123.2 sq cm
136.8 sq cm
135.5 sq cm
12.36 sq cm

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Question 6: This question is available to subscribers only!


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