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### Geometry4.23 The Area of a Sector - I

 Example: The radius of a circle is 28 cm. An arc AB subtends an angle of 105° at the center O. Find the area of the sector OAB. Solution: Given that, r = 28 cm, and x° = Ð AOB = 105 ° The area of the sector OAB = (x / 360) * p * r2 = (105/360) * 22/7 * 28 * 28 = (7 * 22 * 14) / 3 = 2156/3 = 718 2/3 sq cm. Directions: Read the above example carefully and answer the following questions. Also make 10 different examples of your own.

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### Geometry4.23 The Area of a Sector - I

 Q 1: The radius of a circle is 14 cm. An arc AB subtends an angle of 72 ° at the center O. Find the area of the sector OAB.136.8 sq cm12.36 sq cm135.5 sq cm123.2 sq cm Q 2: The radius of a circle is 8.4 cm. An arc AB subtends an angle of 135 ° at the center O. Find the area of the sector OAB.84.69 sq cm86.36 sq cm83.16 sq cm83.00 sq cm Q 3: An arc AB subtends an angle of 240 ° at the center O of a circle. Find the radius of the circle if the area of the sector OAB is given by 102.67 sq cm.9 cm6 cm7 cm8 cm Q 4: An arc AB subtends an angle of 60 °at the center O of a circle. Find the radius of the circle if the area of the sector OAB is given by 147.84 sq cm.14.6 cm12.2 cm15.2 cm16.8 cm Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!