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Online Quiz (Worksheet A B C D)

Questions Per Quiz = 2 4 6 8 10

Grade 7 - Mathematics
6.15 Word Problems - Age

Steps:
1. Read the problem carefully and note down what is given and what is required.
2. Select a letter say x or y or z to represent the unknown quantity asked for.
3. Represent the word statements of the problems in the symbolic language step by step.
4. Look for quantities which are equal as per conditions given and form an equation.
5. Solve the equation.
6. Verify the result for making sure that your answer satisfies the requirements of the problems.

Example:
Five years ago the age of a father was twice the age of his son. The sum of their present ages is 55 years. Find their present ages.
Solution:
The age of the father, 5 years ago = x years
Age of the father 5 years ago = 2x years
Present ages of son and father respectively are (x+5) years and (2x+5)years.
Given that, sum of their present ages = 55 years
Therefore (x+5)+(2x+5) = 55
3x + 10 = 55
3x = 55 - 45
3x = 45
x = 45/3
x = 15

Verification:
Present age of son = x + 5 = 15 + 5 = 20 years
Present age of father = 2x + 5 = 2*15 + 5 = 30 + 5 = 35 years
The sum of their present ages = 20 + 35 = 55 years.

Directions: Solve the following word problems. Also write at least ten word problem examples of your own.
Q 1: The present age of Adam is three times that of his son. Six years ago, the age of Adam was four times that of his son. Find the ratio of their ages 6 years later.
6:4
5:2
5:6
6:3

 Q 2: The present age of Nancy is one fourth that of her mother Christina. 20 years later the age of Nancy will be half the age of her mother. Find their present age.
Nancy 10 years Christina 40 years
Nancy 15 years Christina 30 years
Nancy 15 years Christina 35 years
Nancy 10 years Christina 20 years

Q 3: George aged 50 years, has a daughter Jessica of age 20 years. How many years ago was the age of George three times that of his daughter.
45
5
16
26

 Q 4: The present age of Peter is one sixth the age of Dan. 5 years later the sum of their ages will be 45 years. Find their present ages.
26 years and 5 years respectively
25 years and 6 years respectively
30 years and 5 years respectively
20 years and 8 years respectively

Q 5: The present age of Tim is twice that of Micheal. 30 years from now, age of Tim will be one and a half (1 1/2) times that of Micheal. Find the present ages of Tim and Micheal.
60 years and 30 years respectively
25 years and 60 years respectively
60 years and 35 years respectively
55 years and 40 years respectively

 Q 6: John is 35 years old and his son 7 years now. In how many years will the son be half as old as his father. (Hint equation: 7 + x = 1/2(35 + x) )
35
16
25
21

Question 7: This question is available to subscribers only!

 Question 8: This question is available to subscribers only!


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