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### Grade 7 - Mathematics4.4 Common Binomial Factor - I

 Example: Factorise 3x(2a+5) + 2y(2a+5). Solution: Take p=2a+5, then The given expression can be changed as 3x.p + 2y.p = (3x+2y)p   (Distributive property) Substituting p value, we get = (3x+2y)(2a+5) Therefore 3x(2a+5) + 2y(2a+5) = (3x+2y)(2a+5) Directions: Solve the following problems. Also write at least 10 examples of your own.
 Q 1: Factorise 7x(7x-6) + 2y(7x-6).(7x-2y)(7x-6)(3x-5y)(6x-8)(7x+2y)(7x-6)(2x-y)(4x-3) Q 2: Factorise 6x(7a+9b) - y(7a+9b).(3x-2y)(a-9b)(6x-y)(7a-9b)(6x-y)(7a+9b)(5x-2y)(5a-5b) Q 3: Factorise 9x(16a+5) - 3y(16a+5).(9x-3y)(16a+5)(2x+y)(6a-2)(6x+7y)(6a-4)(9x+3y)(16a-5) Q 4: Factorise 9a(7x-6) - 8b(7x-6).(9a-8b)(7x-6)(3a-8b)(x+6)(9a-8b)(7x+6)(4a-6b)(3x+5) Q 5: Factorise 6x(7a-9) - 3y(7a-9).(2x+3y)(a-9)(5x+y)(4a-7)(6x+3y)(7a-9)(6x-3y)(7a-9) Q 6: Factorise 2x(4a+5) + 3y(4a+5).(2x+3y)(4a+5)(2x+3y)(4a-5)(x+2y)(4a-5)(2x+3y)(2a-2) Question 7: This question is available to subscribers only! Question 8: This question is available to subscribers only!