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### Grade 7 - Mathematics4.5 Factorization - III

 Example: Express 15x2y2 + 6x2yz + 9xyz as product of factors Solution: To find factors first we find HCF of the terms, that is Breaking each monomial simplest numerical literal factors, we get 15x2y2 = 3 * 5 * x * y 6x2yz  = 3 * 2 * x * y * z 9xyz  =  3 * 3 * x * y * z HCF of the terms = 3 * x * y = 3xy 15x2y2 + 6x2yz + 9xyz = 3xy * 5xy + 3xy * 2z +  3xy * 3z  (Since 3xy is the HCF) = 3xy(5xy + 2x + 3z) Directions: Write the given terms as product of factors. Also write at least 10 examples of your own.
 Q 1: Factorise 21x2+28xy+63xz.7x(3x+4y+9z)7x(3x+3y+9z)3x(7x+4y+9z) Q 2: Factorise 42x2y2z+63xy2z2+70x2yz2.7xyz(6xy+9yz+6xz)7xyz(6xy+9yz+10xz)7xyz(6xy+4yz+10xz) Q 3: Factorise 14x2y+21xy2+49xyz.2xy(7x+3y+7z)3xy(2x+7y+7z)7xy(2x+3y+7z) Q 4: Factorise 12x2y + 27xy2+9x2yz.3xy(4x+9y+3xz)3xy(4x+5y+3xz)3xy(4x+9y+3z) Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!