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### Grade 7 - Mathematics4.8 Highest Common Factor - II

 Example: Find the HCF of 12a2b2, 16a3b2, 24a4b3c2. Solution: Break each monomials into the simplest numerical and literal factors. 12a2b2 = 2 * 2 * 3 * a * a * b * b 16a3b2 = 2 * 2 * 2 * 2 * a * a * a * b * b 24a4b3c2 = 2 * 2 * 2 * 3 * a * a * a * a *  b * b * b * c * c Highest numerical factor that divides each monomial = 2 * 2 = 4 Highest literal factor that divides each monomial = a * a * b * b  = a2 * b2 Therefore HCF of given terms = 4a2b2 Directions: Solve the following HCF problems. Also write at least 10 examples of your own.
 Q 1: Find the HCF of 8x2y2, 12x3y2 and 24x4y3z2.None of these4x2y24x2y2z24xy2z Q 2: Find the HCF of 4x3y2z2, 16x4y2z and 20x3yz2.4x3yz4x3y2zNone of these4x2yz2 Q 3: Find the HCF of 9a3b2c, 16a2b3d and 15ab3cd.None of these3ab23ab2cd3a2bc Q 4: Find the HCF of the 14ab2, 28b2c3 and 56ab2c.14ab214b2None of these14ab2c Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!