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Date:___________________

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Grade 8 - Mathematics
1.4 Equations With Decimal Coefficients - II

Example: Solve the equation (0.6)x + 0.02 = x - 1.78.
Solution:
Writing decimals as common fractions, we have
6x/10 + 2/100 = x - 178/100
L.C.M. of denominators 10 and 100 is 100.
\ Multiplying both sides of the equation by 100
60x + 2 = 100x - 178
Transposing 100x to L.H.S. and 2 to R.H.S. we have 60x - 100x = -178 - 2
-40x = -180. Dividing both sides by -40 we get
-40x/-40 = -180/-40
x = 9/2 = 4.5

Verifications:
Substituting x = 4.5 in the equation we get
L.H.S. (0.6)x + 0.02 = (0.6)(4.5) + 0.02 = 2.70
R.H.S. x - 1.78 = 4.5 - 1.78 = 2.72
\ L.H.S. = R.H.S.
\ x = 4.5 is the solution.


Directions: Solve the following problems. Also write at least five equations with decimal coefficients of your own and solve them.

Name: ___________________

Date:___________________

Grade 8 - Mathematics
1.4 Equations With Decimal Coefficients - II

Q 1: Solve the equation (2.6)x - 0.02 = 3x - 5.6.
13.95
14.9
13.5

Q 2: Solve the equation (3.6)x - 1.02 = 2x + 3.2.
211/80
86/112
80
112/78

Q 3: Solve the equation (1.2)x + 2.1 = 9x - 2.2.
43/78
16/17
43/35
78/45

Q 4: Solve the equation (2.4)x - 5.2 = 3x + 4.2.
47/3
17/9
19/14
43/12

Q 5: Solve the equation (1.9)x + 3.1 = 2x + 4.1.
11
-10
14/5
-18

Q 6: Solve the equation (2.1)x - 2.2 = x - 5.2.
-30/19
-30/11
2/14
15/8

Question 7: This question is available to subscribers only!

Question 8: This question is available to subscribers only!


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