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Online Quiz (Worksheet A B C D)

Questions Per Quiz = 2 4 6 8 10

Grade 7 - Mathematics
9.42 Area of the Four Walls of a Room - II

Example:
The perimeter of the floor is 115 metres and the height of the room is 16 metres, find the area of the room and find the cost of painting the four walls at the rate of $620 for 100 square metres.

Solution:
Given that,
Perimeter of the floor = 115 metres.
Height = 16 metres.
Therefore, total area of the four walls A = ph.
ie A = 115 * 16
= 1840 Square metres.
Therefore, total area of the four walls is 1840 square metres.
Cost of the painting the four walls = $ (620 * 1840) / 100
= $ 11,408.

Directions: Read the above example carefully and answer the following questions:
  • If the perimeter of a floor is 12x units and the height of the room is x units, find the area of the floor. Also find the area when x = 5 metres.
    (Answer: 12x2; 60 square metres)


Q 1: The perimeter of the floor is 177 metres. Find the height of the room, if the area of the room is given by 1947 square metres.
11 metres
16 metres
56 metres
29 metres

 Q 2: The height of a room is 15 metres. Find the perimeter of the floor, if the area of the room is given by 2970 square metres.
2630 metres
1350 metres
198 metres
None of these

Q 3: The perimeter of the floor is 175 metres and the height of the room is 9 metres. Find the cost of painting the four walls at the rate of $ 351 for 100 square metres.
$2650.23
$5528.25
$2560.75
$1565.85

 Q 4: The height of a room is 14 metres. Find the perimeter of the floor, if the area of the room is given by 1746 square metres.
276 metres
576 metres
976 metres
126 metres

Q 5: The perimeter of the floor is 160 metres. Find the height of the room, if the area of the room is given by 1920 square metres.
12 metres
17 metres
None of these
29 meters

 Q 6: The perimeter of the floor is 134 metres and the height of the room is 16 metres, find the area of the room.
1144 square metres
3144 square metres
None of these
2144 square metres

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 Question 8: This question is available to subscribers only!


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