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#### Online Quiz (WorksheetABCD)

Questions Per Quiz = 2 4 6 8 10

 Example: In a quadrilateral, two angles are 80° and 120°, the remaining two angles are equal. What is the measure of each of these angles? Solution: Sum of the given angles = 80 + 120 = 200. we know that the sum of the four angles of the quadrilateral is 360°. \ The sum of the remaining two angles = 360 - 200 = 160 But they are equal. \ each angle = 1/2 * 160 = 80°. Example: In a quadrilateral, the second angle is 2 times the first. The remaining 2 angles are equal and each angle is 4 times the first angle. What is the measure of each of these angles? Solution: Let the first angle be 'x'. We know that the sum of the angles of a quadrilateral = 360°. Here, Second angle = 2x; Third angle = Fourth angle = 4x; Therefore x + 2x + 4x + 4x = 360; ie 11x = 360; ie x = 360/11 = 32.73.(Rounded off to nearest hundredth). Hence the first angle is 32.73°, second angle = 2 x 32.73 = 65.46° and third angle = Fourth angle = 4 x 32.73 = 130.92°. Directions: Read the above example carefully and answer the following questions: In a quadrilateral, the first angle is 2 times the second, the remaining two angles are equal and are 5 times the first. What is the measure of each of these angles? In a quadrilateral, two angles are 80° and 100°, the remaining two angles are equal. What is the measure of each of these angles?
 Q 1: In a quadrilateral, two angles are 90° and 150°, the remaining two angles are equal. What is the measure of each of these angles?120°60°90° Q 2: In a quadrilateral, the sum of the first two angles is 200°, the remaining two angles are equal. What is the measure of each of these angles?160°80°90° Q 3: In a quadrilateral, two angles are 50° and 90°, the remaining two angles are equal. What is the measure of each of these angles?100°130°110° Q 4: In a quadrilateral, the sum of the first 2 angles are given by 225°. The remaining two angles are equal. What will be the measure of each of these angles?67.5°67°135° Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!