High School Mathematics - 2 10.18 Trignometry Review

Function

0^{o}

30°

45°

60°

90°

sin

Ö0/2

Ö1/2

Ö2/2

Ö3/2

Ö4/2

cos

Ö4/2

Ö3/2

Ö2/2

Ö1/2

0

tan

0

Ö3/3

1

Ö3

undefined

sec

1

2Ö3/3

Ö2

2

undefined

csc

undefined

2

Ö2

2Ö3/3

1

cot

undefined

Ö3

1

Ö3/3

0

sin

cos

tan

0

0

1

0

90

1

0

infinity

180

0

-1

0

270

-1

0

infinity

Functions of angles in all quadrants in terms of those in quadrant 1

-A

90^{0} ± A P/2 ± A

180^{0} ± A P ± A

270^{0} ± A 3P/2 ± A

360^{0} ± A 2P ± A

sin

-sinA

cos A

±sin A

-cosA

±sin A

cos

cos A

±sin A

-cos A

±sin A

cos A

tan

-tan A

±cot A

± tan A

±cot A

±tan A

csc

-csc A

sec A

± csc A

-sec A

±csc A

sec

sec A

± csc A

-sec A

±csc A

sec A

cot

-cot A

± tan A

± cot A

±tan A

± cot A

Q 1: The angle of elevation of the top of a tower which is yet incomplete at a point 120 metres from its base is 45^{o}. How much higher should it be raised so that the elevation at the same point may become 60^{o}? 36.85 metres 100 metres 87.84 metres

Q 2: A vertical flagstaff stands on a horizontal plane from a point distant 150 metres from its foot, the angle of elevation of its top is found to be 30^{o}, find the height of the flagstaff. 100 metres 100.4 metres 113.4 metres

Q 3: The angles of a triangle ABC are in AP and b:c = 3^{1/2}:2^{1/2}. Find angle A. 60 degrees 45 degrees 75 degrees

Q 4: Find the angle in radian through which a pendulum swings if its length is 75 cm and the tip describes an arc of length 10 cm 2/15 4/15 3/15

Q 5: Find the degree measure of the angle subtended at the centre of a circle of diamter 200 cm by an arc of length 22cm. 45^{o} 12^{o}36^{l} 33^{o}

Q 6: What is the angle of elevation of the sun when the length of the shadow of a pole is 3^{1/2} times the height of the pole? 90^{o} 60^{o} 30^{o}

Q 7: In triangle ABC , if 2 cos A/a + cos B/b + 2 cos C/c = a/bc + b/ca. find angle A 90 degrees 45 degrees 30 degrees

Q 8: Show that cot x.cot 2x - cot 2x cot 3x - cot 3x cot x = 1 Answer:

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Question 10: This question is available to subscribers only!