High School Mathematics - 2 10.18 Trignometry Review

Function

0^{o}

30°

45°

60°

90°

sin

Ö0/2

Ö1/2

Ö2/2

Ö3/2

Ö4/2

cos

Ö4/2

Ö3/2

Ö2/2

Ö1/2

0

tan

0

Ö3/3

1

Ö3

undefined

sec

1

2Ö3/3

Ö2

2

undefined

csc

undefined

2

Ö2

2Ö3/3

1

cot

undefined

Ö3

1

Ö3/3

0

sin

cos

tan

0

0

1

0

90

1

0

infinity

180

0

-1

0

270

-1

0

infinity

Functions of angles in all quadrants in terms of those in quadrant 1

-A

90^{0} ± A P/2 ± A

180^{0} ± A P ± A

270^{0} ± A 3P/2 ± A

360^{0} ± A 2P ± A

sin

-sinA

cos A

±sin A

-cosA

±sin A

cos

cos A

±sin A

-cos A

±sin A

cos A

tan

-tan A

±cot A

± tan A

±cot A

±tan A

csc

-csc A

sec A

± csc A

-sec A

±csc A

sec

sec A

± csc A

-sec A

±csc A

sec A

cot

-cot A

± tan A

± cot A

±tan A

± cot A

Q 1: In triangle ABC, if b = 6, c = 4, cos A = 1/12, find a 4 3^{1/2} 4.3^{1/2}

Q 2: In triangle ABC , if 2 cos A/a + cos B/b + 2 cos C/c = a/bc + b/ca. find angle A 30 degrees 45 degrees 90 degrees

Q 3: From the light house the angles of depression of two ships on opposite sides of the light house are observed to be 30^{o} and 45^{o}. If the height of the light house is 300 metres, find the distance between the ships if the line joining them passes through foot of the light house. 809 metres 800 metres 819.6 metres

Q 4: If in two circlesarcs of the same length subtend angles 60^{o} and 75^{o} at the centre, find the ratio of their radii. 1:2 2:3 5:4

Q 5: What is the angle of elevation of the sun when the length of the shadow of a pole is 3^{1/2} times the height of the pole? 30^{o} 90^{o} 60^{o}

Q 6: Solve the triangle ABC given that A = 67^{o}, b = 3 cms, c = 2 cms. a = 2 cm, B = 73^{o}C = 39^{o} 41^{l} a = 5 cm, B = 70^{o}19^{l}, C = 39^{o} 41^{l} a = 2.88 cm, B = 73^{o}19^{l}, C = 39^{o} 41^{l}

Q 7: Find the length of an arc of a circle of radius 10 cm which subtends an angle of 45^{o} at the centre. 5/4 7/4 3/4

Q 8: Find the radian measure of 15^{o}. /12 /4 /6

Question 9: This question is available to subscribers only!

Question 10: This question is available to subscribers only!