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Grade 7 - Mathematics
4.51 Special Products and Expansions Review Test

Q 1: Find the value of (99)2 using formula.
9801
6034
3304

Q 2: (2x2-5).(7x+1) = _____?
14x3-2x2-35x-5
14x3+2x2-35x-5
14x3+2x2-35x+5

Q 3: (9x-9).(2x-5) = _____?
10x2-63x+45
18x2-63x+50
18x2-63x+45

Q 4: (17x+7) (7y+9) = _____?
119xy+153x+49y+63
119xy+157x+49y+63
129xy+153x+49y+63

Q 5: Find the value of (99)2.
9861
9801
9701

Q 6: Divide (a4-4a3-2a2-9a-4) by (a2+2a+1).
Quotient=(a2-6a+9) and Remainder=(-21a-13)
Quotient=(a2-6a+9) and Remainder=(-21a+13)
Quotient=(a2+6a+9) and Remainder=(-21a-13)

Q 7: Divide [(15a)3+(5b)3] by (15a+5b).
225a2-75ab+25b2
225a2+75ab+25b2
225a3-75ab+25b3

Q 8: Factorise 144x2 - 1.
(12x+1)(12x-1)
(12x-1)(12x-1)
(12x+1)(12x+1)

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Question 10: This question is available to subscribers only!


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