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### High School Mathematics - 210.5 Cosecant, Secant and Cotangent of an Angle

 Cosecant, Secant, Cotangent of an Angle In the right angled triangle ΔPAB, ∠PAB = θ Cosecant csc θ = hypotenuse/opposite = AP/PB Secant sec θ = hypotenuse/ adjacent = AP/AB Cotangent cot θ = adjacent / opposite = AP/PB Then the ratio cot θ = 1; sec θ = Ö2 cot θ = 1/Ö2 sec θ = Ö2 cot θ = Ö2 ; sec θ = 1/Ö2 Directions: Answer the following questions. Also write at least 10 examples of your own.
 Q 1: If sec θ = 2, find sin θ, cot θsin θ = 2Ö3; cot &theta = Ö2sin θ = 1/2; cot θ = Ö3/2sin θ = Ö3/2; cot θ = 1/Ö3sin θ = 2/Ö3; cot &theta = 1 Q 2: Given cot θ = 20/21, determine cos θ, cosec θ.Answer: Q 3: If cosec A = Ö10, find sec A, cot A.sec A = Ö10/3; cot A = 1sec A = 10/3; cot A = 1sec A = 1/3; cot A = 1sec A = Ö10/3; cot A = Ö10/3 Q 4: If sin A = 1/3, evaluate cos A.cosec A.Answer: Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!