 Name: ___________________Date:___________________

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### High School Mathematics - 210.5 Cosecant, Secant and Cotangent of an Angle

 Cosecant, Secant, Cotangent of an Angle In the right angled triangle ΔPAB, ∠PAB = θ Cosecant csc θ = hypotenuse/opposite = AP/PB Secant sec θ = hypotenuse/ adjacent = AP/AB Cotangent cot θ = adjacent / opposite = AP/PB Then the ratio cot θ = 1; sec θ = Ö2 cot θ = 1/Ö2 sec θ = Ö2 cot θ = Ö2 ; sec θ = 1/Ö2 Directions: Answer the following questions. Also write at least 10 examples of your own. Name: ___________________Date:___________________

### High School Mathematics - 210.5 Cosecant, Secant and Cotangent of an Angle

 Q 1: If 7 sin A = 24 cos A, find cot A.Answer: Q 2: Given cot θ = 20/21, determine cos θ, cosec θ.Answer: Q 3: If sin A = 1/3, evaluate cos A.cosec A.Answer: Q 4: If sec θ = 2, find sin θ, cot θsin θ = 1/2; cot θ = Ö3/2sin θ = 2/Ö3; cot &theta = 1sin θ = Ö3/2; cot θ = 1/Ö3sin θ = 2Ö3; cot &theta = Ö2 Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!