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High School Mathematics - 2
10.5 Cosecant, Secant and Cotangent of an Angle

Cosecant, Secant, Cotangent of an Angle

In the right angled triangle ΔPAB, ∠PAB = θ

csc θ = hypotenuse/opposite = AP/PB

sec θ = hypotenuse/ adjacent = AP/AB

cot θ = adjacent / opposite = AP/PB

Then the ratio
cot θ = 1; sec θ = 2
cot θ = 1/2 sec θ = 2
cot θ = 2 ; sec θ = 1/2

Directions: Answer the following questions. Also write at least 10 examples of your own.
Q 1: Given cot θ = 20/21, determine cos θ, cosec θ.

Q 2: If sec θ = 25/7, find the values of tan θ, cosec θ.

Q 3: If sin A = 1/3, evaluate cos A.cosec A.

Q 4: If cosec θ = 41/40, find the values of sin θ, sec θ.

Question 5: This question is available to subscribers only!

Question 6: This question is available to subscribers only!

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