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### High School Mathematics - 210.5 Cosecant, Secant and Cotangent of an Angle

 Cosecant, Secant, Cotangent of an Angle In the right angled triangle ΔPAB, ∠PAB = θ Cosecant csc θ = hypotenuse/opposite = AP/PB Secant sec θ = hypotenuse/ adjacent = AP/AB Cotangent cot θ = adjacent / opposite = AP/PB Then the ratio cot θ = 1; sec θ = Ö2 cot θ = 1/Ö2 sec θ = Ö2 cot θ = Ö2 ; sec θ = 1/Ö2 Directions: Answer the following questions. Also write at least 10 examples of your own.

 Name: ___________________Date:___________________

### High School Mathematics - 210.5 Cosecant, Secant and Cotangent of an Angle

 Q 1: Given cot θ = 20/21, determine cos θ, cosec θ.Answer: Q 2: If sec θ = 25/7, find the values of tan θ, cosec θ.Answer: Q 3: If sin A = 1/3, evaluate cos A.cosec A.Answer: Q 4: If cosec θ = 41/40, find the values of sin θ, sec θ.Answer: Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!