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### High School Mathematics - 27.2 Laws of Logarithms

 Laws log a(mn) = logam + logan log a(m/n) = logam - logan log amn = nlogam Change of base: logbr = logar/logab Example: Find the value of log216Ö8 Solution: log216Ö8 = log216 + log2Ö8--by first law log216 + log281/2 log216 + 1/2log28-- by third law log224 + 1/2log223 4 + 1/2.3 = 11/2--- because log22 = 1 Answer: 11/2 Directions: Solve the following.
 Q 1: log11[121Ö14641/3Ö1331]537 Q 2: Solve for x ; x = log6216Answer: Q 3: log73Ö33715 Q 4: log 327Ö729698 Q 5: log54Ö25/625-7/21/2-13/5 Q 6: log2Ö6/Ö83/21/41/2 Q 7: log23Ö4/42.Ö81/23/4-29/6 Q 8: Prove that 5log3 + log9 = log 2187Answer: Question 9: This question is available to subscribers only! Question 10: This question is available to subscribers only!

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