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High School Mathematics - 2
7.2 Laws of Logarithms

Laws
  1. log a(mn) = logam + logan
  2. log a(m/n) = logam - logan
  3. log amn = nlogam
  4. Change of base: logbr = logar/logab
Example: Find the value of log2168
Solution: log2168 = log216 + log28
--by first law log216 + log281/2
log216 + 1/2log28
-- by third law log224 + 1/2log223
4 + 1/2.3 = 11/2
--- because log22 = 1 Answer: 11/2


Directions: Solve the following.
Q 1: log5425/625
1/2
-7/2
-13/5

Q 2: log26/8
1/2
1/4
3/2

Q 3: log11[12114641/31331]
7
3
5

Q 4: log7333
1
5
7

Q 5: Prove that 5log3 + log9 = log 2187
Answer:

Q 6: Prove that 3log2 + log5 = log 40
Answer:

Q 7: log234/42.8
3/4
1/2
-29/6

Q 8: Solve for x ; x = log6216
Answer:

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Question 10: This question is available to subscribers only!


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