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Online Quiz (Worksheet A B C D)

Questions Per Quiz = 2 4 6 8 10

High School Mathematics
4.48 Curved Surface Area of a Cylinder

If you take a rectangular sheet of paper with length l and height h and connect the two ends you will get a cylinder.
The area of the sheet gives the curved surface area of the cylinder. The length of the sheet is equal to the circumference of the circular base which is equal to 2*pi*r.
So curved surface area of the cylinder = area of the rectangular sheet = length x width
= perimeter of the base of the cylinder x h
Curved surface area = 2 * pi * r * h.

Example:
The ratio of the radius and height of a cylinder is 5:3. The radius is 25cm. Find its curved surface area.
Solution:
Given that, r = 25cm.
Height (h) = 25 * 3/5 = 15cm.
Curved surface area = 2 * pi * r * h.
Here, r = 25cm. and h = 15cm.
= 2 * 22/7 * 25 * 15
= 2357.14 Sq. cm.


Directions: Solve the following problems. Also write at least 5 examples of your own.
Q 1: The ratio of the radius and height of a cylinder is 4:5. The radius is 20cm. Find its curved surface area.
3148.86 Sq. cm.
3146.86 Sq. cm.
3144.86 Sq. cm.
3142.86 Sq. cm.

Q 2: The ratio of the radius and height of a cylinder is 3:4. The radius is 21cm. Find its curved surface area.
3694 Sq. cm.
3692 Sq. cm.
3698 Sq. cm.
3696 Sq. cm.

Q 3: The ratio of the radius and height of a cylinder is 5:2. The radius is 35cm. Find its curved surface area.
3070 Sq. cm.
3060 Sq. cm.
3080 Sq. cm.
3090 Sq. cm.

Q 4: The ratio of the radius and height of a cylinder is 4:3. The radius is 16cm. Find its curved surface area.
1206.86 Sq. cm.
1208.86 Sq. cm.
1204.86 Sq. cm.
1202.86 Sq. cm.

Q 5: The ratio of the radius and height of a cylinder is 5:6. The radius is 25cm. Find its curved surface area.
4718.29 Sq. cm.
4714.29 Sq. cm.
4712.29 Sq. cm.
4716.29 Sq. cm.

Q 6: The ratio of the radius and height of a cylinder is 7:5. The radius is 35cm. Find its curved surface area.
5500 Sq. cm.
5510 Sq. cm.
5520 Sq. cm.
5530 Sq. cm.

Question 7: This question is available to subscribers only!

Question 8: This question is available to subscribers only!


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