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High School Mathematics - 2
13.7 Binomial Distribution

Binomial Distribution


Sometimes we may be interested in the happening of a certain event A of S and the 2 outcomes can be :(a) A happens (b)A does not happen
For eg:If a die is tossed and and we are interested in the finding that A = {5} .The occurence of A is called 'success' and can be denoted by S. So P(S)=1/6 and P(F)= 1-1/6 =5/6.
Such trials with 2 outcomes are called Bernoulli Trials.
Let us perform an action involving repetition of Bernoulli trials.
Let the constant probability of success be p and that of failure be q. Then the probability of getting x successes from n independent trials is given by

P(x) = nCx.px.qn-x.

Solved Example
An unbiased coin is tossed 6 times. Find the probability of getting (a)3 heads,(b)at least 4 heads.

Solution
6 independent trials are carried out . So n = 6
The probability of success, i.e getting a head = p = 1/2.
The probability of failure, i.e getting a tail = q = 1/2.
P(x) = 6Cx.1/2x.1/26-x.
P(x) = 6Cx.1/26.
Case a Now consider the first case. When exactly three heads are obtained x= 3.
P(3) = 6C3.1/26 = 5/16
Case b When exactly 4 heads are obtained, x = 4 or 5 or 6. P(4)+P(5)+P(6) = 6C4.1/26 + 6C5.1/26 + 6C6.1/26.
= 1/26.[6C4 + 6C5 + 6C6]
= 11/32
Q 1: A cubic die is thrown 4 times. What is the probability of obtaining at least 1 six
671/1296
345/1296
761/1296
431/1296

Q 2: An ordinary coin is tossed 4 times. Find the probability of getting no heads.
1/16
1/8
1/32
1/4

Q 3: In a certain game, the probability of A's winning a game is 2/3. Find the probability of A's winning at last 4 games out of 5.
191/243
112/243
119/243
121/243

Q 4: In a specific University it is observed that on an average 1 student out of 5 is an Indian. Find the probability that at least 1 student out of 3 is an Indian .
17/143
16/231
61/125
1834/2349

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Question 6: This question is available to subscribers only!


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