Sue is 8 and two-third years older than Jill. The sum of their ages is 23 years. How old is Jill?
Let 's' stand for Sue's age and 'j' stand for Jill's age.
Sue is 8 and two-third years older than Jill: s = 8 + (2/3)j
The sum of their ages is 23 years: s + j = 23 that means s = 23-j
s = 8 + (2/3)j substitute s = 23-j
23-j = 8 + (2/3)j
23 - 8 = j + (2/3)j
15 = (5/3)j
3 = (1/3)j
3 = j/3
j = 9 year old
s = 23 - j = 23 - 9 = 14
Jill is 9 years old and Sue is 14 years old.
Bob is three years older than Sally. The sum of the ages of Bob and Sally is seven. How old is Bob?
Let 'b' stand for Bob's age and 's' stand for Sally's age.
Bob is three years older than Sally: b = s + 3
The sum of the ages of Bob and Sally is seven: b + s = 7
s + 3 + s = 7
2s + 3 = 7
2s = 7-3
2s = 4
s = 2
b = s+3 = s +3 = 5
Bob is 5 years old.
Three times Sally's age five years ago is same as sixty less than six times her current age. How old is Sally?
Let 's' be Sally's present age. Three years ago Sally's age is s - 3
3(s-5) = 6s - 60
3s-15 = 6s - 60
60-15 = 6s - 3s
45 = 3s
s = 45/3
s = 15
Directions: Solve the following word problems.