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### Math Word Problems - GED, PSAT, SAT, ACT, GRE Preparation3.11 Word Problems - Age - 3

 Example: Sue is 8 and two-third years older than Jill. The sum of their ages is 23 years. How old is Jill? Solution: Let 's' stand for Sue's age and 'j' stand for Jill's age. Sue is 8 and two-third years older than Jill: s = 8 + (2/3)j The sum of their ages is 23 years: s + j = 23 that means s = 23-j s = 8 + (2/3)j substitute s = 23-j 23-j = 8 + (2/3)j 23 - 8 = j + (2/3)j 15 = (5/3)j 3 = (1/3)j 3 = j/3 j = 9 year old s = 23 - j = 23 - 9 = 14 Jill is 9 years old and Sue is 14 years old. Example: Bob is three years older than Sally. The sum of the ages of Bob and Sally is seven. How old is Bob? Solution: Let 'b' stand for Bob's age and 's' stand for Sally's age. Bob is three years older than Sally: b = s + 3 The sum of the ages of Bob and Sally is seven: b + s = 7 s + 3 + s = 7 2s + 3 = 7 2s = 7-3 2s = 4 s = 2 b = s+3 = s +3 = 5 Bob is 5 years old. Example: Three times Sally's age five years ago is same as sixty less than six times her current age. How old is Sally? Solution: Let 's' be Sally's present age. Three years ago Sally's age is s - 3 3(s-5) = 6s - 60 3s-15 = 6s - 60 60-15 = 6s - 3s 45 = 3s s = 45/3 s = 15 Directions: Solve the following word problems.
 Q 1: Cathy is 9 years older than Nancy. Mallory is 1 year younger than twice Nancy's age. Together, their ages add up to 80. How old is Mallory? (Hint: c = n + 9, m= 2n-1, c+n+m = 80, m=?)183524 Q 2: Twelve years ago, mother was seven times as old as her daughter. Their present ages are in the ratio of 5:2. Find their present ages. mother is 25 years and daughter is 10mother is 40 years and daughter is 16mother is 30 years and daughter is 12 Question 3: This question is available to subscribers only! Question 4: This question is available to subscribers only!