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### Math Word Problems - GED, PSAT, SAT, ACT, GRE Preparation3.10 Word Problems - Age - 2

 Method 1: Step 1: Convert the sentences into equations with different variables. Two equations with 2 variables or three equations with 3 variables etc Step 2: Solve the equations with variables to get the solution. Example: Emma is nine years older than Kate. Emma is four times as old as Betsy was three years ago. Betsy is eighteen years younger than Emma. How old is Kate? Solution: Let 'e' be the present age of Emma and 'k' and 'b' be the current ages of Kate and Betsy respectively. "Emma is nine years older than Kate" can be written as e = k + 9 "Emma is four times as old as Betsy was three years ago" can be written as: e - 3 = 4(b-3) "Betsy is eighteen years younger than Emma" can be written as: b = e - 18 e = k + 9 e - 3 = 4(b-3) b = e - 18 k = ? e - 3 = 4(b-3) substituting b = e - 18 in the equation e - 3 = 4(b-3) e - 3 = 4(e - 18-3) e - 3 = 4(e - 21) e - 3 = 4e - 84 e - 3 = 4e - 84 3e = 81 e = 81/3 = 27 b = e - 18 = 27 - 18 = 9 e = k + 9 => 27 = k+9 => k = 27-9 = 18 Emma is 27 years old, Betsy is 9 years and Kate is 18 years old. Verification: Emma is 9 years older than Kate: e = k + 9 = 18+9 = 27 Emma is four times as old as Betsy was three years ago. e - 3 = 4(b-3) 4(b-3) = 4(9-3) = 4(6) = 24 e - 3 = 27 - 3 = 24 Betsy is eighteen years younger than Emma: b = e - 18= 27 - 18 = 9 Method 2: Step 1: Convert the sentences into equations with one variables. Identify the unknown. It is the variable you want to find out. Write the first equation and all other equations with respect to the same variable. Step 2: Solve the equation with one variables to get the solution. Example: The age of the father is 4 years more than three times the age of son. Three years hence, father's age will be 16 years more than twice the age of his son. Determine their present ages. Solution: Let the present age of son = x years Father's age = 3x + 4 years Three years hence, son's age = x + 3 years Father's age = 3x + 4 + 3 = 3x + 7 years 3x + 7 = 2(x + 3) + 16 3x + 7 = 2x + 6 + 16 3x - 2x = 6 + 16 - 7 x = 15 3x + 4 = 3 x 15 + 4 = 49 The son's age is 15 years and father's age = 49 years Directions: Solve the following word problems. You can use either of the methods to find the solution.
 Q 1: Jill is twice as old as Lisa. 5 years ago, Jill was thrice as old as Lisa was then. Find their present ages. Lisa is 11 years and Jill is 22 yearsLisa is 10 years and Jill is 20 yearsLisa is 15 years and Jill is 30 years Q 2: Alison is now 3 times as old as Emma. In 5 years, Allison will be 2 times as old as Emma will be then. Find their present ages. Allison is 12 years and Emma is 4 yearsAllison is 15 years and Emma is 5 yearsAllison is 18 years and Emma is 6 years Q 3: Harry is 25 years older than Peter. In 5 years, Harry will be 2 times as old as Peter will be then. What are their present ages? Harry is 45 and Peter is 20 yearsHarry is 52 and Peter is 22 yearsHarry is 41 and Peter is 12 years Q 4: Mary is 60 years old now and Kim is 25 years old. In how many years will Mary be twice as old as Kim?10 years30 years12 years Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!

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