Example:
Factorize, 4a2+4ab+b2-c2.
Solution:
Given that, 4a2+4ab+b2-c2.
We can write this as,
[(2a)2+2.2a.b+(b)2]-c2
This is in the form of (a+b)2 = a2+2ab+b2.
Here a = 2a and b = b, substitute these values in the formula, we get,
= (2a+b)2-c2
This is in the form of a2-b2 = (a+b)(a-b)
Here a = 2a+b and b = c, Substitute these values in the formula, we get,
= (2a+b+c)(2a+b-c)
Directions: Solve the following problems. Also write at least 10 examples of your own.
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