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### Grade 8 - Mathematics4.11 Set Operations - Intersection

 n(AÇB) = n(A) + n(B) - n(AÈB) Example: n(A) = 7, n(B) = 5 and n(AÈB) = 9 then find n(AÇB) Solution: n(AÇB) = n(A) + n(B) - n(AÈB). = 7 + 5 - 9 = 12 - 9 = 3 n(AÇB) = 3 Directions: Solve the following problems. Also write at least five examples of your own.
 Q 1: n(A) = 15, n(B) = 19 and n(AÈB) = 19 then find n(AÇB).15121314 Q 2: n(A) = 10, n(B) = 8 and n(AÈB) = 12 then find n(AÇB).10486 Q 3: n(A) = 15, n(B) = 10 and n(AÈB) = 16 then find n(AÇB).6897 Q 4: n(A) = 11, n(B) = 4 and n(AÈB) = 14 then find n(AÇB).5934 Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!

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