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### Grade 8 - Mathematics4.11 Set Operations - Intersection

 n(AÇB) = n(A) + n(B) - n(AÈB) Example: n(A) = 7, n(B) = 5 and n(AÈB) = 9 then find n(AÇB) Solution: n(AÇB) = n(A) + n(B) - n(AÈB). = 7 + 5 - 9 = 12 - 9 = 3 n(AÇB) = 3 Directions: Solve the following problems. Also write at least five examples of your own.

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### Grade 8 - Mathematics4.11 Set Operations - Intersection

 Q 1: n(A) = 10, n(B) = 8 and n(AÈB) = 12 then find n(AÇB).46810 Q 2: n(A) = 15, n(B) = 10 and n(AÈB) = 16 then find n(AÇB).6978 Q 3: n(A) = 9, n(B) = 9 and n(AÈB) = 10 then find n(AÇB).816186 Q 4: n(A) = 11, n(B) = 4 and n(AÈB) = 14 then find n(AÇB).4539 Q 5: n(A) = 13, n(B) = 15 and n(AÈB) = 16 then find n(AÇB).11121310 Q 6: n(A) = 12, n(B) = 9 and n(AÈB) = 13 then find n(AÇB).4678 Question 7: This question is available to subscribers only! Question 8: This question is available to subscribers only!