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### Grade 8 - Mathematics3.41 Ring - II

 Example: The area of circular park is 2464 square metres. A path of width 7 metres is laid around and inside of it. Find the area of the path. Solution: The area of the circular part of the outer ring. Let its radius be R metres. So, pR2 = 2464 R2 = 7/22 * 2464 R2 = 7 * 112 R2 = 784 Taking square root on both sides. R = 28 Let the radius of the inner ring be r metres. Therefore, R - r = 7 So, r = R - 7 r = 28 - 7 r = 21 Therefore, the area of the circular path = p(R + r)(R - r) = 22/7 * 49 * 7 = 12166/7 = 1738 Square metres. Directions: Solve the following problems. Also write at least ten examples of your own.

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### Grade 8 - Mathematics3.41 Ring - II

 Q 1: The area of circular park is 154 square metres. A path of width 3.5 metres is laid around and inside of it. Find the area of the path.115.5 Sq. mt.125.5 Sq. mt.1155 Sq. mt.115 Sq. mt. Q 2: The area of circular park is 616 square metres. A path of width 4.9 metres is laid around and inside of it. Find the area of the path.35.574 Sq. mt.3557.4 Sq. mt.35574 Sq. mt.355.74 Sq. mt. Q 3: The area of circular park is 3850 square metres. A path of width 0.7 metres is laid around and inside of it. Find the area of the path.15246 Sq. mt.1524 Sq. mt.1524.6 Sq. mt.152.46 Sq. mt. Q 4: The area of circular park is 1386 square metres. A path of width 17.5 metres is laid around and inside of it. Find the area of the path.1347 Sq. mt.13475 Sq. mt.1347.5 Sq. mt.134.75 Sq. mt. Q 5: The area of circular park is 5544 square metres. A path of width 2.8 metres is laid around and inside of it. Find the area of the path.7145.6 Sq. mt.714.56 Sq. mt.71456 Sq. mt.7146 Sq. mt. Q 6: The area of circular park is 7546 square metres. A path of width 1.4 metres is laid around and inside of it. Find the area of the path.4250.4 Sq. mt.4254 Sq. mt.425.4 Sq. mt.425.04 Sq. mt. Question 7: This question is available to subscribers only! Question 8: This question is available to subscribers only!