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 Example: In a quadrilateral, the diagonals intersect at right and have lengths equal to 9 cm and 10 cm. respectively. Find the area of the quadrilateral. Solution: Area of quadrilateral = 1/2 * d1d2 Given that, d1 = 9cm. and d2 = 10 cm. Area = 1/2 * 9 * 10 A = 9 * 5 A = 45 Sq. cm. Directions: Solve the following problems. Also write at least ten examples of your own.
 Q 1: In a quadrilateral, the diagonals intersect at right and have lengths equal to 7.8 cm and 9.4 cm. respectively. Find the area of the quadrilateral.36.62 Sq. cm.36.66 Sq. cm.36.64 Sq. cm.36.68 Sq. cm. Q 2: In a quadrilateral, the diagonals intersect at right and have lengths equal to 9.8 cm and 10.4 cm. respectively. Find the area of the quadrilateral.50.6 Sq. cm.50.46 Sq. cm.50.9 Sq. cm.50.96 Sq. cm. Q 3: In a quadrilateral, the diagonals intersect at right and have lengths equal to 6.4 cm and 9.5 cm. respectively. Find the area of the quadrilateral.30.6 Sq. cm.30.4 Sq. cm.30.8 Sq. cm.30.2 Sq. cm. Q 4: In a quadrilateral, the diagonals intersect at right and have lengths equal to 7.8 cm and 9.6 cm. respectively. Find the area of the quadrilateral.37.44 Sq. cm.37 Sq. cm.37.4 Sq. cm.37.46 Sq. cm. Q 5: In a quadrilateral, the diagonals intersect at right and have lengths equal to 15.6 cm and 13.3 cm. respectively. Find the area of the quadrilateral.103.76 Sq. cm.103.74 Sq. cm.103.72 Sq. cm.103.78 Sq. cm. Q 6: In a quadrilateral, the diagonals intersect at right and have lengths equal to 6.9 cm and 7.9 cm. respectively. Find the area of the quadrilateral.27.255 Sq. cm.27.25 Sq. cm.27 Sq. cm.27.2 Sq. cm. Q 7: In a quadrilateral, the diagonals intersect at right and have lengths equal to 7.6 cm and 9.4 cm. respectively. Find the area of the quadrilateral.35.7 Sq. cm.35.72 Sq. cm.35.75 Sq. cm.35.5 Sq. cm. Q 8: In a quadrilateral, the diagonals intersect at right and have lengths equal to 17.4 cm and 15.5 cm. respectively. Find the area of the quadrilateral.134.5 Sq. cm.134.8 Sq. cm.134.85 Sq. cm.134 Sq. cm. Question 9: This question is available to subscribers only! Question 10: This question is available to subscribers only!