|Method 2: |
Step 1: Write all the equations in terms of one variable.
Step 2: Solve the equation
The tens digit of a two-digit number is two more than the ones digit. The number is thirty more than four times the sum of the digits. What is the number?
Let the ones digit be 'x'
Tens digit is two more than the ones digit = x + 2
The number is 10(x+2) + x
Thirty more than four times the sum of the digits so 4(x + x + 2) +30
Therefore, the number is thirty more than four times the sum of the digits can be written as
10(x + 2) + x = 4(x + x + 2) + 30
10(x + 2) + x = 4(2x + 2) + 30
10x + 20 + x = 8x + 8 + 30
11x + 20 = 8x + 38
11x - 8x = 38 - 20
3x = 18
x = 18/3 = 6
the number in tens place is x + 2 = 6 + 2 = 8
The number is 86.
Directions: Solve the following word problems.