Example:
Find the angle of a sector of a circle whose area is 1/4^{th} of the circle.

Solution:
Area of a circle = pr^{2}.
Area of a sector is = q/360^{o}pr^{2}.
Here (1/4)pr^{2} = (q/360^{o})pr^{2}.
i.e 1/4 = q/360^{o}
i.e q = 360/4 = 90^{o}.

Directions: Read the above example carefully and answer the following questions. Also write 10 examples of your own.